Thread t6 = new Thread(s, "consumer3"); t1.start(); t2.start(); t3.start(); t4.start(); t5.start(); t6.start(); } } class Semaphore public synchronized void acquire() { public synchronized void release() {
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正在阅读:攻克学习多线程时碰到的难题攻克学习多线程时碰到的难题
2004-03-26 10:05
出处:PConline
责任编辑:linjixiong
键盘也能翻页,试试“← →”键