正在阅读:如何取得文本框中包含指定字符串的行如何取得文本框中包含指定字符串的行

2004-04-21 10:05 出处:CSDN 作者:northwolves 责任编辑:linjixiong
  文本框属性为允许多行显示时,由于是软回车实现的分行,无法用SPLIT(TEXT1.TEXT,VBCRLF)准确地取出指定行的内容。本文利用SENDMESSAGE 系列函数,通过发送文本框消息,实现了获取包含指定字符串的行,并演示了如何获取文本框中文本总行数和任意指定行的文本内容。

  'add a textbox with "multiline=true","scrollbars=2".

  Private Declare Function SendMessage Lib "USER32" Alias "SendMessageA" _
  (ByVal hWnd As Long, ByVal wMsg As Long, ByVal wParam As Long, _
  lParam As Any) As Long
  Private Declare Function SendMessageByNum Lib "USER32" _
  Alias "SendMessageA" (ByVal hWnd As Long, ByVal wMsg As Long, _
  ByVal wParam As Long, ByVal lParam As Long) As Long
  Private Declare Function SendMessageByString Lib "USER32" Alias _
  "SendMessageA" (ByVal hWnd As Long, ByVal wMsg As Long, ByVal wParam _
  As Long, ByVal lParam As String) As Long

  Private Const EM_LINEINDEX = &HBB
  Private Const EM_GETLINECOUNT = &HBA
  Private Const EM_GETLINE = &HC4
  Private Const EM_LINELENGTH = &HC1

  Function GetLineText(ByVal txtbox As TextBox, ByVal LineIndex As Long) As String '返回指定行的内容
  Dim lc As Long, linechar As Long
  linechar = SendMessageByNum(txtbox.hWnd, EM_LINEINDEX, LineIndex, 0)
  lc = SendMessageByNum(txtbox.hWnd, EM_LINELENGTH, linechar, 0) + 1
  GetLineText = String(lc + 2, 0)
  Mid(GetLineText, 1, 1) = Chr(lc And &HFF)
  Mid(GetLineText, 2, 1) = Chr(lc \ &H100)
  lc = SendMessageByString(txtbox.hWnd, EM_GETLINE, LineIndex, GetLineText)
  GetLineText = Left(GetLineText, lc)
  End Function

  Function getlinewithstr(ByVal txtbox As TextBox, ByVal mystr As String) As String
  Dim linecount As Long, temp() As String, i As Long
  linecount = SendMessage(txtbox.hWnd, EM_GETLINECOUNT, 0, 0) '返回行数
  ReDim temp(1 To linecount)
  For i = 1 To linecount
  temp(i) = "第" & i & "行:" & GetLineText(txtbox, i - 1) '添加行号
  Next
  getlinewithstr = Join(Filter(temp, mystr), vbCrLf) ' 字符串过滤
  Erase temp
  End Function

  Private Sub Command1_Click()
  MsgBox getlinewithstr(Text1, "CSDN"), 0, "包含“CSDN”的行"
  End Sub

  Private Sub Form_Load()
  Dim a(25) As String, i As Long
  For i = 0 To 25
  a(i) = String(50, Chr(i + 97))
  Next
  Text1.Text = Join(a, "CSDN")

  End Sub

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